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4.9x^2+5x-40=0
a = 4.9; b = 5; c = -40;
Δ = b2-4ac
Δ = 52-4·4.9·(-40)
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{809}}{2*4.9}=\frac{-5-\sqrt{809}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{809}}{2*4.9}=\frac{-5+\sqrt{809}}{9.8} $
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